Congrats to the winners of Puzzle #114!
Aimee G. (Royal Oak), Esther S. (Grand Rapids), Judy M. (Buffalo), Anthony U. (Rochester), Vicki H. (Orlando), Loni (Tampa), Bryan S.(Jacksonville), Danny T. (Miami), Angela J. (Chicago), Drew T. (Washington D.C.), Ben A. (Providence), Wendy (Akron), and Sarah S. (Pittsburgh). And our Facebook winners: Sharletha S. (Royal Oak), Nate C. (Grand Rapids), Bonnie S. (Buffalo), Jarcelyn L. (Rochester), Diana S. (Orlando), Noel M. (Tampa), Curtis F. (Jacksonville), N/A (Miami), Heather P. (Chicago), N/A (Washington D.C.), Liza F. (Providence), Russ H. (Akron), and Kelly K. (Pittsburgh).
The answer to Puzzle #114 was:
Since each one of the students have one answer wrong, this means that each one of them have two answers right. Assuming that Student A has the wrong answer to the first question, Student B also has the wrong answer for the first question. We then know that the other 2 answers from Students A and B are correct. However, since the answers are different that isn't possible. So now, both Student A and Student B must be right with the first question and the answer to the first question is two. Keep applying the same logic and you will find the answers below: Q1. Two Q2. Three Q3. Two
Puzzle #115: Try out this Garam puzzle!
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